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What is the hydraulic loading rate of a trickling filter with a flow rate of 6250 gpm and diameter of 140'?

400 GPD/ft2

585 GPD/ft2

To determine the hydraulic loading rate of a trickling filter, you first need to calculate the area of the filter based on its diameter and then use the flow rate to find the hydraulic loading rate.

The area (A) of a circular filter can be calculated using the formula:

\[ A = \pi \times (r^2) \]

where \( r \) is the radius. The diameter of the filter is given as 140 feet, so the radius is half of that:

\[ r = \frac{140}{2} = 70 \text{ feet} \]

Now you can calculate the area:

\[ A = \pi \times (70)^2 \approx 3.14 \times 4900 \approx 15386 \text{ square feet} \]

Next, the hydraulic loading rate (HLR) is calculated by dividing the flow rate by the area:

1. Convert the flow rate from gallons per minute (gpm) to gallons per day (GPD):

\[ 6250 \text{ gpm} \times 1440 \text{ minutes/day} = 9000000 \text{ GPD} \]

2. Now, calculate the hydraulic loading rate:

\[ H

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700 GPD/ft2

900 GPD/ft2

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